2(y^2-y)=.5(4y^2+10)

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Solution for 2(y^2-y)=.5(4y^2+10) equation:


Simplifying
2(y2 + -1y) = 0.5(4y2 + 10)

Reorder the terms:
2(-1y + y2) = 0.5(4y2 + 10)
(-1y * 2 + y2 * 2) = 0.5(4y2 + 10)
(-2y + 2y2) = 0.5(4y2 + 10)

Reorder the terms:
-2y + 2y2 = 0.5(10 + 4y2)
-2y + 2y2 = (10 * 0.5 + 4y2 * 0.5)
-2y + 2y2 = (5 + 2y2)

Add '-2y2' to each side of the equation.
-2y + 2y2 + -2y2 = 5 + 2y2 + -2y2

Combine like terms: 2y2 + -2y2 = 0
-2y + 0 = 5 + 2y2 + -2y2
-2y = 5 + 2y2 + -2y2

Combine like terms: 2y2 + -2y2 = 0
-2y = 5 + 0
-2y = 5

Solving
-2y = 5

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '-2'.
y = -2.5

Simplifying
y = -2.5

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